Integrand size = 24, antiderivative size = 109 \[ \int \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \, dx=\frac {4^{-p} e^{-\frac {4 a}{b}} \Gamma \left (1+p,-\frac {4 \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )}{b}\right ) \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \left (-\frac {a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )}{b}\right )^{-p}}{c^4 d^2 f} \]
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Time = 0.10 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2436, 2336, 2212, 2495} \[ \int \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \, dx=\frac {4^{-p} e^{-\frac {4 a}{b}} \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \left (-\frac {a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )}{b}\right )^{-p} \Gamma \left (p+1,-\frac {4 \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )}{b}\right )}{c^4 d^2 f} \]
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Rule 2212
Rule 2336
Rule 2436
Rule 2495
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \left (a+b \log \left (c \sqrt {d} \sqrt [4]{e+f x}\right )\right )^p \, dx,c \sqrt {d} \sqrt [4]{e+f x},c \sqrt {d \sqrt {e+f x}}\right ) \\ & = \text {Subst}\left (\frac {\text {Subst}\left (\int \left (a+b \log \left (c \sqrt {d} \sqrt [4]{x}\right )\right )^p \, dx,x,e+f x\right )}{f},c \sqrt {d} \sqrt [4]{e+f x},c \sqrt {d \sqrt {e+f x}}\right ) \\ & = \text {Subst}\left (\frac {4 \text {Subst}\left (\int e^{4 x} (a+b x)^p \, dx,x,\log \left (c \sqrt {d} \sqrt [4]{e+f x}\right )\right )}{c^4 d^2 f},c \sqrt {d} \sqrt [4]{e+f x},c \sqrt {d \sqrt {e+f x}}\right ) \\ & = \frac {4^{-p} e^{-\frac {4 a}{b}} \Gamma \left (1+p,-\frac {4 \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )}{b}\right ) \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \left (-\frac {a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )}{b}\right )^{-p}}{c^4 d^2 f} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00 \[ \int \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \, dx=\frac {2^{-2 p} e^{-\frac {4 a}{b}} \Gamma \left (1+p,-\frac {4 \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )}{b}\right ) \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \left (-\frac {a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )}{b}\right )^{-p}}{c^4 d^2 f} \]
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\[\int \left (a +b \ln \left (c \sqrt {d \sqrt {f x +e}}\right )\right )^{p}d x\]
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\[ \int \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \, dx=\int { {\left (b \log \left (\sqrt {\sqrt {f x + e} d} c\right ) + a\right )}^{p} \,d x } \]
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\[ \int \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \, dx=\int \left (a + b \log {\left (c \sqrt {d \sqrt {e + f x}} \right )}\right )^{p}\, dx \]
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none
Time = 0.06 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.64 \[ \int \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \, dx=-\frac {4 \, {\left (b \log \left (\sqrt {\sqrt {f x + e} d} c\right ) + a\right )}^{p + 1} e^{\left (-\frac {4 \, a}{b}\right )} E_{-p}\left (-\frac {4 \, {\left (b \log \left (\sqrt {\sqrt {f x + e} d} c\right ) + a\right )}}{b}\right )}{b c^{4} d^{2} f} \]
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\[ \int \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \, dx=\int { {\left (b \log \left (\sqrt {\sqrt {f x + e} d} c\right ) + a\right )}^{p} \,d x } \]
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Timed out. \[ \int \left (a+b \log \left (c \sqrt {d \sqrt {e+f x}}\right )\right )^p \, dx=\int {\left (a+b\,\ln \left (c\,\sqrt {d\,\sqrt {e+f\,x}}\right )\right )}^p \,d x \]
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